dbcli/sqlglot
1
0
Fork 0
Code Issues Activity

Adding upstream version 6.0.4.

Browse source 
Signed-off-by: Daniel Baumann <daniel@debian.org>
This commit is contained in:
Daniel Baumann 2025-02-13 06:15:54 +01:00
parent d01130b3f1
commit 527597d2af
Signed by: daniel
GPG key ID: FBB4F0E80A80222F
122 changed files with 23162 additions and 0 deletions
Download patch file Download diff file Expand all files Collapse all files

41
tests/fixtures/optimizer/pushdown_projections.sql vendored Normal file
View file

@ -0,0 +1,41 @@
SELECT a FROM (SELECT * FROM x);
SELECT "_q_0".a AS a FROM (SELECT x.a AS a FROM x AS x) AS "_q_0";
SELECT 1 FROM (SELECT * FROM x) WHERE b = 2;
SELECT 1 AS "_col_0" FROM (SELECT x.b AS b FROM x AS x) AS "_q_0" WHERE "_q_0".b = 2;
SELECT (SELECT c FROM y WHERE q.b = y.b) FROM (SELECT * FROM x) AS q;
SELECT (SELECT y.c AS c FROM y AS y WHERE q.b = y.b) AS "_col_0" FROM (SELECT x.b AS b FROM x AS x) AS q;
SELECT a FROM x JOIN (SELECT b, c FROM y) AS z ON x.b = z.b;
SELECT x.a AS a FROM x AS x JOIN (SELECT y.b AS b FROM y AS y) AS z ON x.b = z.b;
SELECT x1.a FROM (SELECT * FROM x) AS x1, (SELECT * FROM x) AS x2;
SELECT x1.a AS a FROM (SELECT x.a AS a FROM x AS x) AS x1, (SELECT 1 AS "_" FROM x AS x) AS x2;
SELECT x1.a FROM (SELECT * FROM x) AS x1, (SELECT * FROM x) AS x2;
SELECT x1.a AS a FROM (SELECT x.a AS a FROM x AS x) AS x1, (SELECT 1 AS "_" FROM x AS x) AS x2;
SELECT a FROM (SELECT DISTINCT a, b FROM x);
SELECT "_q_0".a AS a FROM (SELECT DISTINCT x.a AS a, x.b AS b FROM x AS x) AS "_q_0";
SELECT a FROM (SELECT a, b FROM x UNION ALL SELECT a, b FROM x);
SELECT "_q_0".a AS a FROM (SELECT x.a AS a FROM x AS x UNION ALL SELECT x.a AS a FROM x AS x) AS "_q_0";
SELECT a FROM (SELECT a, b FROM x UNION SELECT a, b FROM x);
SELECT "_q_0".a AS a FROM (SELECT x.a AS a, x.b AS b FROM x AS x UNION SELECT x.a AS a, x.b AS b FROM x AS x) AS "_q_0";
WITH y AS (SELECT * FROM x) SELECT a FROM y;
WITH y AS (SELECT x.a AS a FROM x AS x) SELECT y.a AS a FROM y;
WITH z AS (SELECT * FROM x), q AS (SELECT b FROM z) SELECT b FROM q;
WITH z AS (SELECT x.b AS b FROM x AS x), q AS (SELECT z.b AS b FROM z) SELECT q.b AS b FROM q;
WITH z AS (SELECT * FROM x) SELECT a FROM z UNION SELECT a FROM z;
WITH z AS (SELECT x.a AS a FROM x AS x) SELECT z.a AS a FROM z UNION SELECT z.a AS a FROM z;
SELECT b FROM (SELECT a, SUM(b) AS b FROM x GROUP BY a);
SELECT "_q_0".b AS b FROM (SELECT SUM(x.b) AS b FROM x AS x GROUP BY x.a) AS "_q_0";
SELECT b FROM (SELECT a, SUM(b) AS b FROM x ORDER BY a);
SELECT "_q_0".b AS b FROM (SELECT x.a AS a, SUM(x.b) AS b FROM x AS x ORDER BY a) AS "_q_0";