43 lines
1.7 KiB
SQL
43 lines
1.7 KiB
SQL
SELECT 1 FROM z;
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SELECT 1 FROM c.db.z AS z;
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SELECT 1 FROM y.z;
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SELECT 1 FROM c.y.z AS z;
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SELECT 1 FROM x.y.z;
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SELECT 1 FROM x.y.z AS z;
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SELECT 1 FROM x.y.z AS z;
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SELECT 1 FROM x.y.z AS z;
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WITH a AS (SELECT 1 FROM z) SELECT 1 FROM a;
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WITH a AS (SELECT 1 FROM c.db.z AS z) SELECT 1 FROM a;
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SELECT (SELECT y.c FROM y AS y) FROM x;
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SELECT (SELECT y.c FROM c.db.y AS y) FROM c.db.x AS x;
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SELECT * FROM x PIVOT (SUM(a) FOR b IN ('a', 'b'));
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SELECT * FROM c.db.x AS x PIVOT(SUM(a) FOR b IN ('a', 'b')) AS _q_0;
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----------------------------
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-- Expand join constructs
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----------------------------
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-- This is valid in Trino, so we treat the (tbl AS tbl) as a "join construct" per postgres' terminology.
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SELECT * FROM (tbl AS tbl) AS _q_0;
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SELECT * FROM (SELECT * FROM c.db.tbl AS tbl) AS _q_0;
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SELECT * FROM ((tbl AS tbl)) AS _q_0;
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SELECT * FROM (SELECT * FROM c.db.tbl AS tbl) AS _q_0;
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SELECT * FROM (((tbl AS tbl))) AS _q_0;
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SELECT * FROM (SELECT * FROM c.db.tbl AS tbl) AS _q_0;
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SELECT * FROM (tbl1 AS tbl1 JOIN tbl2 AS tbl2 ON id1 = id2 JOIN tbl3 AS tbl3 ON id1 = id3) AS _q_0;
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SELECT * FROM (SELECT * FROM c.db.tbl1 AS tbl1 JOIN c.db.tbl2 AS tbl2 ON id1 = id2 JOIN c.db.tbl3 AS tbl3 ON id1 = id3) AS _q_0;
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SELECT * FROM ((tbl1 AS tbl1 JOIN tbl2 AS tbl2 ON id1 = id2 JOIN tbl3 AS tbl3 ON id1 = id3)) AS _q_0;
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SELECT * FROM (SELECT * FROM c.db.tbl1 AS tbl1 JOIN c.db.tbl2 AS tbl2 ON id1 = id2 JOIN c.db.tbl3 AS tbl3 ON id1 = id3) AS _q_0;
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SELECT * FROM (tbl1 AS tbl1 JOIN (tbl2 AS tbl2 JOIN tbl3 AS tbl3 ON id2 = id3) AS _q_0 ON id1 = id3) AS _q_1;
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SELECT * FROM (SELECT * FROM c.db.tbl1 AS tbl1 JOIN (SELECT * FROM c.db.tbl2 AS tbl2 JOIN c.db.tbl3 AS tbl3 ON id2 = id3) AS _q_0 ON id1 = id3) AS _q_1;
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